
Anthony T. answered 03/03/22
Patient Science Tutor
The balanced equation Fe(s) +CuSO4(aq) →Cu(s)+FeSO4(aq), indicates that Cu(s) is produced from CuSO4 in the ratio of the molecular mass of CuSO4 to the atomic mass of Cu(s). From the periodic table, this ratio is found to be 159.6 g CuSO4 / 63.546 g Cu.
Using this ratio, the mass of Cu(s) found can be multiplied by the above ratio:
159.6 g CuSO4 / 63.546 g Cu. x 0.122 g Cu = 0.306 g CuSO4 in 150 mL of the sample. To convert this to moles, divide by the molecular mass of CuSO4.
0.306 g / 159.6 g/mole = 0.00192 moles. As this is in 150 mL of solution, the molarity is
0.00192 moles / 150 mL x 1000 mL/L = 0.0128 M.
Please check math.