If 725.0g of glucose yields 137.8mL of ethanol, what is the percent yield for the reaction?

Answer 1

Start with the balanced equation: C6H12O6 → 2C₂H₅OH + 2CO₂

Convert grams of glucose to moles of glucose using the molecular weight to get about 4.02 moles of glucose.

For every mole of glucose, we get 2 moles of ethanol, so we should get 8.04 moles of ethanol.

Convert to grams to get about 370.0 grams of ethanol

Convert to mL using density of ethanol to get 292.3 mL of ethanol.

Percent yield: (137.8 / 292.3) * 100% = 47.1%