I don’t understand how to solve this?

Question

The distribution of actual weights of wedges of cheddar cheese produced at a dairy is normal with a mean of 9.1 ounces and a standard deviation of 0.2 ounces. (Round to 2 decimal places for all z-values and round all other answers to 4 decimal places, if needed.)

(a) The probability that a randomly chosen wedge of cheddar cheese is greater than 9.07 is _____.

(b) If a sample of 16 is randomly chosen, then the distribution of the sample mean weight is _____(b2) with a mean of _____ and a standard deviation of _____. (Options for (b2): approximately normal or not normal or left/right skewed)

(c) The probability that the sample mean weight of this sample of 16 is less than 9.07 is ______.

(d) The probability that the sample mean weight of this sample of 16 is greater than 9.07 is ______.

(e) The probability that the sample mean weight of this sample of 16 is between 9.07 and 9.15 is ______.

(f) There is only a 5% chance that the average weight of a sample of these 16 cheese wedges will be below _______.

Answer 1

Hi Mia L.,

Please read the response to your other, very similar question and apply the comments there to this problem. Same basic skills being applied! Just cheese wedge weights, instead of student scores or whatever it was, as the initial data. Then pooling (averaging), and recalc the sample deviation, then apply normal probability tables.

And please quit submitting multiple questions on the same skill set, or your questions will be flagged and reported.

-- Cheers (but not cheeses!), --Mr. d.