
Stanton D. answered 02/22/22
Tutor to Pique Your Sciences Interest
Hi Samuel A.,
You probably should be able to run these probabilities yourself? How many cards are there total (12)? And how many of those cards have a digit "1" (anywhere) on them (exactly 4 of them). So do the division, and express as a decimal value or as an exact fraction. So the probability that a (single) drawn card does NOT have a 1 on it is = 1 MINUS the value you just found for the probability that it DOES.
Of course, if you did draw a card with a 1, you could shrug it off with "I guess it was just in the cards."?? (that means, fated to happen)
-- Cheers, -- Mr. d.