Inactive Tutor answered 02/22/22
Hi Samuel A.,
You probably should be able to run these probabilities yourself? How many cards are there total (12)? And how many of those cards have a digit "1" (anywhere) on them (exactly 4 of them). So do the division, and express as a decimal value or as an exact fraction. So the probability that a (single) drawn card does NOT have a 1 on it is = 1 MINUS the value you just found for the probability that it DOES.
Of course, if you did draw a card with a 1, you could shrug it off with "I guess it was just in the cards."?? (that means, fated to happen)
-- Cheers, -- Mr. d.