Huaizhong R. answered 06/18/25
Ph.D. Extensive knowledge/Experience in Math Learning/Teaching
Using the binomial expansion
(1+x)n = C(n,0) +C(n,1)x + ... + C(n,k)xk + ... + C(n,n)xn, and taking derivatives on both sides would yield
n(1 + x)n-1 = C(n,1) + 2C(n,2)x + ... + kC(n,k)xk-1 + nC(n,n)xn-1.
Letting x =1 does the job.