what is the volume

Question

Calculate the volume of 0.129 M sodium hydroxide required to neutralize 13.0 mL of a 0.197 M hydrochloric acid solution.

Answer 1

The balanced equation:

NaOH(aq)+HCl(aq)→NaCl(aq)+HOH(l)

Conversions:

0.197 mol HCl = 1000mL HCl

1 mol HCl=1 mol NaOH

1000 mL NaOH=0.129 mol NaOH

go from mL HCl to mol HCl, to mol NaOH, to volume NaOH

13.0mL HCl (0.197 mol HCl / 1000mL HCl) (1mol NaOH / 1 mol HCl) (1000 mL NaOH / 0.129 mol NaOH)=19.8527

19.9mL NaOH