What is the magnitude and direction of electric field at a point midway between two equal and opposite charges of 3.5x10-8C which are 5m apart?

Answer 1

Use Coulomb's law where F=kq₁q₂/r² where q₁ = q₂ = 3.5E-8 and r = 5 meters ... k= coulomb's constant = 3E9 ... since charges are both positive the force is of repulsion = 4.41E-7