Chris P.

asked • 02/08/22

What mass of NaOH is in 280 mL of a 1.9 M NaOH solution?

Keka K.

M = moles/L of solution 1.9 = X/0.280 L moles = (1.9) ( 0.28) = 0.532 mass in g = moles . MW = 21.28 g
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02/09/22

Keka K.

M = moles/L. and moles = mass/MW
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02/09/22

1 Expert Answer

By:

Shawn A. answered • 02/12/22

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To find the mass of sodium hydroxide (NaOH), you must first multiply the Volume (in Liters!) times the Molarity (mol/L)

V= 280mL = 0.280L


M x V = moles

1.9 mol/L x 0.280L = 0.53 moles of NaOH (there are only 2 significant figures in 1.9M so this is rounded)

Now that you have moles of NaOH, you must convert from moles to mass by multiplying by the molar mass of NaOH which is 40.00g/mol.


0.53mol NaOH x 40.00g/mol NaOH = 21g (again rounded to 2 significant figures.



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