Mat D.

asked • 02/07/22

Prove that mn^k is even if k > 0

Let n, m, k be integers where n is even and m is odd. Prove that mn^k is even if k > 0.

I know intuitively that n^k can just be expressed as an even number, because n is even. But is that a valid proof?

1 Expert Answer


Ryan B. answered • 02/09/22

5.0 (176)

7+ years tutoring Logic and Discrete Mathematics

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