22. How would you prepare 270 mL of 0.55M Al2(SO4)3 solution from a 3.0M Al2(SO4)3 stock solution?

Answer 1

Take 270 mL and multiply by the conversion factor of 1 L / 1000 mL. Multiply the 0.270 L by 0.55 mol Al2(SO4) 3 / 1 L to get mol Al2(SO4)3. Multiply 0.1485 mol Al2(SO4)3 by 1 L / 3.0 mol Al2(SO4)3 to get the volume of stock solution. Dilute to form 270 mL of solution. Be sure to round to 2 significant figures.