Inactive Tutor answered 02/04/22
Circumference = piD = 2pir = R-4s where R=rope length and r = the circle's radius
r = (R-4s)/2pi
pir = (R-4s)/2
Area = pir(r) = (R-4s)^2/4pi
Area = f(s) =(1/pi) ((R-4s)/2)^2
or
f(s) = R^2/4pi - 2R/pi + 4/pi
Kya W.
asked 02/04/22A piece of rope that is feet long is cut into two pieces. One piece is used to form a circle and the other used to form a square. Write a function representing the area of the circle as a function of the length of one side of the square
Hint: If is the circumference of the circle and is the perimeter of the square, then
Enter the expression in simplest form.
f(s) =
Inactive Tutor answered 02/04/22
Circumference = piD = 2pir = R-4s where R=rope length and r = the circle's radius
r = (R-4s)/2pi
pir = (R-4s)/2
Area = pir(r) = (R-4s)^2/4pi
Area = f(s) =(1/pi) ((R-4s)/2)^2
or
f(s) = R^2/4pi - 2R/pi + 4/pi
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.