What is the correct set up for this problem?

Question

1 Fe₂O₃ (s) + 6 HCl (g) --> 2 FeCl₃ (s) + 3 H₂O (g)

How many grams of HCl are needed to react with 27.62 g of Fe₂O_3?

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= 37.29 g HCl

Answer 1

Basic stoichiometry problem take given quantity place over one using dimensional analysis convert to moles using the molar mass, then using molar ratios in balanced equation multiply by conversion factor 6 mol HCl/ 1mol Fe2O3, finally multiply by 36.45g HCl/ 1 mol HCl

27.62g Fe2O3/1 x 1 mol Fe2O3/ 159.7g Fe2O3 x 6 mol HCl/ 1 mol Fe2O3 x 36.45g HCl/ 1 mol HCl