How many grams of NH3 can be produced ( theoretically) from the reaction of 5.0g of N2 and 5.0g of H2

Answer 1

N₂+3H₂-->2NH₃

convert g to mol with molar mass:

5g N2 / 28 g/mol = 0.1785 mol N2

5g H2 / 1 g/mol = 5 mol H2

convert mol to mol with coefficients

0.1785 mol N2 (2 mol NH3 / 1 mol N2)=0.3571 mol NH3 theoretically

5 mol H2 (2 mol NH3 / 3 mol H2)= 3.33 mol NH3 theoretically

actual theoretical yield is the smaller value, so N2 is the limiting reactant, so 0.3571 mol NH3 is predicted to form.

convert moles to grams with molar mass

0.3571 mol NH3 (17.04 g NH3 / 1 mol NH3)= 6.0857 g NH3