Find the exact value of sin (2𝜃) given sec 𝜃 = 11/3 and 0

Question

Find the exact value of sin (2𝜃) given sec 𝜃 = 11/3 and 0 < 𝜃 < 𝜋/2.

Stephen H. · Accepted Answer

sin2x=2sinxcosx ... secx = 1/cosx=11/3 thus cosx = 3/11 ... note that sinx =sqrt(1-9/121)=sqrt(112)/11. Now sin2x=2sinxcosx=2sqrt(112)/11(3/11)=6sqrt(112)/121= 6/121*4*sqrt(7)=24/121*sqrt7/.

Find the exact value of sin (2𝜃) given sec 𝜃 = 11/3 and 0 < 𝜃 < 𝜋/2.

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Find the exact value of sin (2𝜃) given sec 𝜃 = 11/3 and 0 < 𝜃 < 𝜋/2.

1 Expert Answer

Still looking for help? Get the right answer, fast.

OR

RELATED TOPICS

RELATED QUESTIONS

Two forces of 55N and 85N act on an object simultaneously and the resultant force is 125N. What is the measurement of the angle between the two forces?

What are the values of all the cube roots (Z = -4v3 - 4i)?

1/x-1/2=2-x/2x

I need help trying to sole tan^2 x =1 where x is more than or equal to 0 but x is less than or equal to pi

how do i solve these?

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