Use Coulomb's law to show 45=9*109QaQb/(.23)2. Since Qa=2Qb the previous equation can be simplified to be 45=9*109*2Qa2. Solve to find Qa=.707*10-4 C and Qb=.354*10-4 C
Javier C.
asked 01/27/22What is the magnitude of the charges?
Two-point charges, A and B, are separated by a distance of 23cm. The magnitude of the charge on A is twice that of the charge on B. If each charge exerts a force of magnitude 45N on the other, find the magnitudes of the charges.
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