Raymond B. answered 02/08/22
Math, microeconomics or criminal justice
5, 30 and 7 of different colors
total 42
5/42 times 4/41 for one way to get the same color
30/42 times 29/41 for another way
7/42 times 6/41 is a 3rd way
add them up to get the probability of having 2 of the same color on 2 draws without replacement
= (5/42)(4/41) + (30/42)(29/41) + (7/42)(6/41)
= (20 + 870 + 42)/(41)(42) = 932/1722 = about 54%