Stanton D. answered 01/19/22
Tutor to Pique Your Sciences Interest
Hi Tina K.,
Looks like KCl has a simple cubic lattice? You should look that up, but I THINK so. Then set up a diagram of the reflection from the (1 1 0) plane. First figure what the lattice spacing (1 0 0) is, using the molar mass of KCl and the stated density of crystal. (1 mole of KCl ions fill up (2*6.023^10^23)^(1/3) positions on any x or y or z axis.) Then figure what the spacing between (1 1 0) planes is, by comparison, using 3-D geometry -- it's quite simple, it's just a plane tilted towards you at a 45 degree angle. Use your diffraction knowledge then; for the particular radiation you MUST have a 1 lambda pathlength difference between the planes, towards that 8 degree angle. (So that they have constructive interference, right?) That will solve for lambda, directly.
-- Cheers, -- Mr. d.