Calculate the number of moles of Na¿CS, produced from 0.60 moles of CS2 by the following reaction. (0,40 mol NazCS,) 3 CS2 + 6 NaOH - 2 NazCS3 + NazCOy + 3 H20

Answer 1

3 CS₂ + 6 NaOH → 2 Na_zCS₃ + NazCOy + 3 H2O

This is weird because we don't know the formula of NazCOy, nor NazCS3. It's extremely likely that the formulas are Na2CO3 and Na2CS3, but that doesn't really matter here.

Given:

0.60 mol CS2

Desired:

? mol NazCS3

Use the molar ratio from the coefficients:

3 mol CS₂ = 2 mol Na_zCS₃

(0.60 mol CS₂ / 1) × (2 mol Na_zCS₃ / 3 mol CS₂) = 0.40 mol Na_zCS₃