M1V1 = M2V2
remember, M = mol/L
convert both mL to L by dividing by 1000
20.0 ml/1000 ml = 0.020 L
12.6 ml/1000 ml = 0.0126 L
M1(0.020 L) = (0.25 M)(0.0126 L) = 0.16M
Krishi S.
asked 01/11/22A 20.0 mL sample of ammonia was titrated with 12.6 mL of 0.25 mol/L HCl. What was the initial concentration of the ammonia?
A) 0.16mol/L
B) 0.097mol/L
C) 0.25mol/L
D) none of these
M1V1 = M2V2
remember, M = mol/L
convert both mL to L by dividing by 1000
20.0 ml/1000 ml = 0.020 L
12.6 ml/1000 ml = 0.0126 L
M1(0.020 L) = (0.25 M)(0.0126 L) = 0.16M
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