Sam W. answered 12/17/21
MD with background in economics, experience tutoring medical students.
This question is touching on the concept of colligative properties. Both boiling point elevation and freezing point depression are proportionally related to the solutes dissolved (Raout's Law). However, there is a difference in the actual changes due to differences in the solvent constants. Let's look at the two equations to see where the difference comes into play:
Boiling point elevation: DeltaT = change in temperature; Kb = molal boiling point elevation constant (different for each solvent); m = molal concentration of solute.
DeltaT = Kb*m
Freezing point depression: Kf = molal freezing point depression constant
DeltaT = Kf*m
Kb and Kf vary depending on the solvent; however, for water and most solvents Kf is greater than Kb meaning there will be a greater magnitude of change in freezing point depression than magnitude of freezing point depression.
The most likely answer is: The magnitude of boiling point elevation is "always less than" the freezing point depression for a certain concentration of solute in the aqueous solution.