
Jon S. answered 12/17/21
Patient and Knowledgeable Math and English Tutor
Ho: p = 0.44
Ha: p != 0.44
a)
sample proportion (phat) = 49/100 = 0.49
sample size (n) = 100
z = (phat - p)/sqrt(p * (1-p)/n) = (0.49 - 0.44)/sqrt(0.44 * 0.56/100) = 1.01
for a two sided test:
p-value = P(z > 1.01) + P(z < -1.01)
since normal distribution is symmetric that is the same as 2 * P(z < -1.01)
P(z < -1.01) = 0.1562, so p-value is 0.3124.
since p-value > alpha (0.01), we cannot reject Ho and conclude any differences
b) here phat = 59/100 = 0.59
z = (0.59 - 0.44)/sqrt(0.44 * 0.56/100) = 3.02
p-value = 2*( P(z < -3.02) = 0.0013
since p-value < alpha, we can reject Ho and conclude differences