chemistry labflow

Question

Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat patients with low blood sugar.

Suppose you prepare a glucose solution using the described procedure.

1. Step 1: Dissolve 210.6 g of glucose in enough water to make 500.0 mL of solution.
2. Step 2: Transfer 24.1 mL of the solution to a new flask and add enough water to make 250.0 mL of dilute solution.

What is the concentration (in M) of the glucose solution at the end of the procedure?

Answer 1

The definition of Molar is moles/liter. We have (210.6g/180.16) or 1.169 moles of glucose. That is dissolved in 500 ml, or 0.5 liters. That means the concentration of the glucose solution is (1.169moles/0.5L) = 2.338 M (4 sig figs).

24.1 ml (0.0241L) of the 2.338M solution is dissolved in 250 ml (0.250L).

The moles of glucose in 24.1 ml: (2.338 moles/Liter)*(0.0241L) = 0.05634 moles

Then dilute the 0.05634 moles to 250 ml (0.250L): (0.05634 moles)/(.250L) = 0.2254M