Chemistry: Molarity and Solution Stoichiometry

Question

2HCl(aq)+Na2CO3(aq)→2NaCl(aq)+H2O(l)+CO2(g)

What volume of 3.00 M HCl in liters is needed to react completely (with nothing left over) with 0.750 L of 0.300 M Na2CO3? 

I'm struggling with how to start this problem, please help.

Answer 1

This is like a standard stoichiometry problem ( g --> moles --> moles --> g) except you are going from volume of sodium carbonate to moles sodium carbonate to moles of HCl to volume of HCl solution:

Start with the extensive variable (how much stuff)

.75 liter * (.3 moles SC/ liter of SC soln)(2 moles HCl/1 mole SC)(1 liter HCl solution/3 moles HCl) = liters HCl solution where SC is sodium carbonate.