How many grams are in 8.74 × 10²⁵ molecules of I₂?

Answer 1

First we need to convert the amount of molecules of I₂ to the moles of I₂ by diving by Avogadro's number as follows.

8.74x10²⁵/6.022x10²³=145.13 moles of I₂

Next we need to convert the moles of I₂ into grams of I₂ by multiplying by the molar mass of diatomic iodine.

145.13 moles * 253.81g/moles= 36,837g or 36.837 kg of I₂, which is an enormous amount of I₂