
Yefim S. answered 12/02/21
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By definition 0 ≤ arcosx ≤ π cos(arccosx) = x; sin(arc√cosx) = √(1 - x2); 4tan(arccosx) = 4√(1 - x2)/x
Alex W.
asked 12/02/21Write the expression as an algebraic expression in x for x > 0.
4 tan(arccos x)
Yefim S. answered 12/02/21
Math Tutor with Experience
By definition 0 ≤ arcosx ≤ π cos(arccosx) = x; sin(arc√cosx) = √(1 - x2); 4tan(arccosx) = 4√(1 - x2)/x
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