A uniform disk of radius 35.1 cm and mass 600 g is rolling across

Question

A uniform disk of radius 35.1 cm and mass 600 g is rolling across a horizontal surface without slipping with a linear speed of 30.3 cm/s.

A. What is the angular velocity of the disk?

𝜔 =  rad/s

B. What is the moment of inertia of the disk?

I =  kg·m²

C.What is the total kinetic energy of the disk?

K =  J

Answer 1

w=v/r = 30.3/35.1=.863 rad/sec

I = 1/2mr²=1/2*(.6)*.351)² = .0369 kg-m²

KE = 1/2Iw²+1/2mv²=.0413Joules