
Andrew F. answered 11/30/21
Experienced Private High School Math Teacher
Alex, let "x" = cos(gamma) and think about this problem as 8x2 + 4x = 0 you would factor and solve for "x" easily --this just has another bit at the end
(8x)(x + 1/2) = 0
The "another bit at the end" is figuring out when cos(gamma) = those values for "x" within the given range.
Hope this helps, but please let me know--Andrew

Andrew F.
I can help you get to the answer, but I don't think it is helpful to give the answer. What values did you get for "x?" (see my previous work) Can you then see what cos(gamma) must equal?11/30/21
Alex W.
Could you please continue the problem11/30/21