$10 invested at 12% compounded continuously after a period of 4 years

Answer 1

A = Pe^rt = 10e^.12(4) = 10e^.48 = about $16.20 compounded continuously

if it had been compounded annually, after

1 year it would be 10x1.12= $11.20,

two years 10x1.12x1.12 = $12.54

three years 10x1.12x1x1.2x1.2 = $14.05,

4 years 12x1.2x1.2x1.2 = $15.76