Let f be the volume fraction of LMT and (1-f) the volume fraction of water. We make the assumption that the volumes add (which they almost certainly do not for miscible liquids). The mass balance for the first part:
fρLMT + (1-f)ρW = 2.427 g/cm3
you are given density of the water, but density of the LMT is 2.95*density of water to convert it to g/cm3
You can solve for f using algebra and get the volume fraction of each constituent.
The second part, you solve the same thing except you want the mix that gets you to 2.522 g/cm3 (new f, 1-f)
In order to know the volumes, just multiply total volume by f. Don't round until you give an answer and your worst sig figs was the specific density at 3SF.