Determine the number of molecules of Cr2O3 that form when 1.34 x 10^3 g of oxygen completely reacts according to the following equation: 4Cr(s) + 3O₂(g) → 2Cr₂O₃(s)

Answer 1

Stoichiometry: (1.34 x 10³ g O₂) * (1 mole O₂ /32.00 g O₂) * (2 mole Cr₂O₃ /3 mole O₂) * (6.022 x 10²³ particles /1 mole) = 1.68 X 10²⁵ molecules of Cr₂O₃