The specific heat of a certain type of cooking oil is 1.75 J/(g⋅°C). How much heat energy is needed to raise the temperature of 2.52 kg of this oil from 23 °C to 191 °C?

Answer 1

So the equation we’re interested in here is q=mcT.

Q=heat energy

M=mass of the object absorbing the heat energy

C=specific heat (typically in Joules/gram * Degree Temperature)

T = change in temperature

Hopefully this helps! If not, scroll down for how to solve。

We know C=1.75 J/(g * C), that m=2.52 kg, and that we need to raise the temperature by 191-23=168 degrees C.

The first trap is that we’re given a mass in kilograms, but our specific heat involves grams.

So let’s convert: 2.52kg * 1000g/kg = 2520 g.

Then, we multiple: Q= 1.75 J /(g * C) * 2520 g * 168 C.

We cancel out units to get: Q =1.75 J * 2520 * 168

Q=740880 Joules