The temperature of a sample of lead increased by 22.3 °C when 255 J of heat was applied. What is the mass of the sample?

Answer 1

Hi again!

So the equation we’re interested in here is q=mcT.

Q=heat energy

M=mass of the object absorbing the heat energy

C=specific heat (typically in Joules/gram * Degree Temperature)

T = change in temperature

This time, though, we're not given the specific heat. However, we are given the material (lead), and according to the both U of Texas website and hyperphysics, lead's specific heat is 0.129 J/(g * C).

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We know C= 0.129 J/(g*C), 255J of heat are added, and the temperature is raised by 22.3C.

Thus, we can set up our Q=mcT equation:

255J = 0.129 J/(g*C) * mass (unknown) * 22.3 C

Cancelling out, we get:

255 = 0.129 /(g) * mass (unknown) * 22.3

Isolating the mass, we get:

88.643 g = mass