Starting with the following equation, Fe₂O₃(s) + C(s) → Fe(l) + CO₂(g) calculate the mass in grams of Fe₂O₃ that will be required to produce 395 grams of Fe.

Answer 1

First, balance the reaction: 2 Fe₂O₃ + 3 C --> 4 Fe + 3 CO₂. Then (395 g Fe) * (1 mole Fe /55.845 g Fe) * (2 mole Fe₂O₃ / 4 mole Fe) * (159.69 g Fe₂O₃ /1 mole Fe₂O₃) = 565 g Fe₂O₃.