Anthony T. answered 11/16/21
Patient Science Tutor
First determine the molecular mass of NaHCO3 = 84 g/mole. A 0.10 molar solution has 0.10 moles in 1000 mL of solution.
100 mL of this solution will then have 0.10 moles / 1000 mL x 100 mL moles of NaHCO3 = 0.01 moles.
84.0 g /mole x 0.01 moles = 0.84 g NaHCO3 needed. (Note: I rounded atomic masses to a whole number).
Abbie D.
Thank you so much!11/16/21