
Yefim S. answered 11/09/21
Math Tutor with Experience
lny = lnx + 2xlna + x2; y'/y = 1/x + 2lna + 2x; y' = (1/x + 2lna + 2x)(xa2xex^2) = (1 + 2xlna + 2x2)a2xex^2 = 0
1 + 2xlna + 2x2 = 0; D = ln2a - 2 < 0, because e - √2 < a < e√2; ln(e - √2) < lna < √2.
So there is no x for what y' = 0.
So, this function has no stationary points.