consider the line y=2x-3.

Question

consider the line y=2x-3.

find the equation of the line that is perpenduclar to this line and passes through the point (-5,2)

find the equation of the line that is parallel to this line passes through the point (-5,2)

Answer 1

The slope of the line y = 2x -3 is 2.

The slope of the line perpendicular to that line is -1/2

since line goes through point (-5,2), equation in point-slope form is:

y-2 = -1/2 ( x + 5)

The slope of the line parallel to that line is 2

so equation in point slope form is:

y-2 = 2 (x + 5)