If 7.93 mol of NO2 occupy 49.7 L, how many liters will 4.38 mol of NO2 occupy at the same temperature and pressure?

Answer 1

With ideal behavior and the same pressure and temperature, use the ratio PV₂ / PV₁ = n₂ RT /n₁ RT, so V₂ = V₁ n₂ / n₁ = (49.7 L) (4.38 mole) / (7.93 mole) = 27.4 L.