A 16.0 L sample of oxygen gas has a pressure of 24.0 atm at a certain temperature. At the same temperature, what volume would this gas occupy at a pressure of 2.50 atm? Assume ideal behavior.

Answer 1

With ideal behavior and the same temperature, the ratio P₂V₂ / P₁V₁ = n₂ RT₂ /n₁ RT₁ = 1, so (2.50 atm) V₂ = (24.0 atm) (16.0 L), V₂ = 384 / 2.50 = 154 L.