Sherwood P. answered 11/05/21
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A | B | A V B
T | T | T
T | F | T
F | T | T
F | F | F
A ∨ B
B
is not valid because the 2nd row in the above truth table is a counterexample.
This is the case where A V B is true but B is False.
2.
C| D |~C | C V D | D V ~C | (C V D) ^ (D V `C)
T | T | F | T | T | T
T | F | F | T | F | F
F | T | T | T | T | T
F | F | T | F | T | F
C V D
D V ~C
D
is a valid argument based on the above truth table, where D = (C V D) ^ (D V ~ C) for all rows.