using molarity to find solute mass and solute volume

Question

A chemist adds 1.85 L of a 1.15 mol/L aluminum chloride AlCl3 solution to a reaction flask. Calculate the millimoles of aluminum chloride the chemist has added to the flask. Round your answer to 3 significant digits.

Answer 1

Hi Monica,

molarity - no of moles / L (or volume)

Therefore:

no of moles = molarity x volume = 1.15 mole / L x 1.85 L = 2127.5 mol =2130 mmol