Inactive Tutor answered 10/31/21
Tutor
New to Wyzant
cosθ = - √1 - 1/49 = -√48/49 = - 4√3/7; θ/2 in quadrant I.
a. sinθ/2 = √(1- cosθ)/2 = √(1 + 4√3/7)2 = √(7 +4√3)/14
bcosθ/2 = √(1+cosθ)/2 = √(1 - 4√3/7)2 = √(7 - 4√3)/14