
Yefim S. answered 10/31/21
Math Tutor with Experience
cosθ = - √1 - 1/49 = -√48/49 = - 4√3/7; θ/2 in quadrant I.
a. sinθ/2 = √(1- cosθ)/2 = √(1 + 4√3/7)2 = √(7 +4√3)/14
bcosθ/2 = √(1+cosθ)/2 = √(1 - 4√3/7)2 = √(7 - 4√3)/14
Imposter S.
asked 10/31/21If sin θ =1/7 and t is in quadrant II, find the following;
a. sin (θ/2) b. cos = (θ/2)
with an explanation if possible... <3
Yefim S. answered 10/31/21
Math Tutor with Experience
cosθ = - √1 - 1/49 = -√48/49 = - 4√3/7; θ/2 in quadrant I.
a. sinθ/2 = √(1- cosθ)/2 = √(1 + 4√3/7)2 = √(7 +4√3)/14
bcosθ/2 = √(1+cosθ)/2 = √(1 - 4√3/7)2 = √(7 - 4√3)/14
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