Stoichiometry Problems.

Question

2C4H10 + 13O2 → 8CO2 + 10H2O

1. How many grams of CO2 would result from a reaction involving 3 x 105 g of C4H10 ?

Answer 1

In order to do the proper stoichiometry we should convert the grams of C4H10 to moles, and from there we can obtain the grams of CO2. We know that for 2 moles of C4H10 there are 8 moles of CO2. So plugging these numbers into the roadmap should generate the answer.

3X10^5 g C4H10 X(1 mole C4H10/58 gC4H10) = 5172 moles C4H10

5172 moles C4H10 X (8 moles CO2/ 2 moles C4H10) = 20,688 moles CO2

20,688 moles CO2 (44 g CO2/1 mol CO2) = 9.1X10^5 g CO2