N2 + 3H2 → 2NH3
First, we need to identify the molar mass of Nitrogen and Ammonia:
- N2 = 28.01 g/mol
- NH3 = 17.03 g/mol
Then we will set up our analysis:
300 g NH3 × 1⁄17.03 NH3 × 1 mol N2/ 2 mol NH3 × 28.01 N2/1 = 246.71 g N2
≈ 247 g N2
Fun fact: This reaction is called the "Haber process"!
If there are any questions or errors please let me know. :)