
Yefim S. answered 10/29/21
Math Tutor with Experience
- sec-1(cscθ) = sec-1(sec(π/2 - θ)) = π/2; 0 < θ < π
- cos-1x + cos-1(- x) = cos-1x + π - cos-1x = π
- tan-1(cotθ) = tan-1(tan(π/2 - θ)) =π/2 - θ; 0 < θ < π

Bode L.
asked 10/29/21I had three problems I can’t figure out at all.
Yefim S. answered 10/29/21
Math Tutor with Experience
Dayv O. answered 10/29/21
Caring Super Enthusiastic Knowledgeable Trigonometry Tutor
wouldn't this work -- note added parts in bold, and k=0 or +/-1,+/-2, ...
sec-1[cscθ]=sec-1[sec(π/2-θ]
=π/2-θ+2πk=(π/2)*(4k+1)-θ
or sec-1[cscθ] =(π/2+θ)+2πk=(π/2)*(4k+1)+θ
for principal value of sec-1, k must be chosen so 0<sec-1[cscθ]<π
same with tan-1cot(θ) sort of
tan-1cot(θ)=π/2-θ+πk=(π/2)*(2k+1)-θ
for principal value of tan-1cot(x), k must be chosen so -π/2<tan-1cot(x)<π/2
for cos-1x+cos-1(-x)
cos-1x equals some angle, call it β and actually it is +/- β
cos-1(-x) equals same +/- β but π radians away from original +/- β
so cos-1x+cos-1(-x) could equal π or equal either π+/- 2*β
if principal value is meant, then cos-1x>0 and cos-1(-x)>0
and cos-1x+cos-1x=π
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Dayv O.
in #1.why can't θ=101π/3 or any number other than when sin(θ)=0,,,,,,,,,,,, and isn't f^-1(f(Q))=Q10/29/21