Determine the molarity of a solution containing 6.76 g BaCl2 in 750.0 mL of solution

Answer 1

Molarity - The concentration of a solution expressed in moles of solute per liter of solution

M = moles

L

PREP WORK:

1. determine molar mass of BaCl₂
2. molar mass Ba: 137.327g/mol
3. molar mass Cl₂: 2(35.453) g/mol = 70.906 g/mol
4. molar mass BaCl₂: 137.327g/mol + 70.906g/mol = 208.233g/mol BaCl₂
5. convert mL of solution to L of solution
6. 750.0 mL _x 1 L = 0.750 L

1000 mL

STEP 1:

Use stoichiometry to convert g BaCl₂ to mol BaCl₂

6.76 g BaCl₂ x 1 mol = 0.0325 mol BaCl₂

208.233g

STEP 2:

Put it all together

M [=] mol = 0.0325 mol BaCl₂ = 0.0433 M BaCl₂ ← ANSWER

L 0.750L