Use this equation: M1V1=M2V2
M1 = 15.7, V1=?,
M2 = 0.10, V2 = 600.0 mL
V1 = M2V2/M1 = 600.0*.1/15.7 = 3.822 mL
Mo K.
asked • 10/28/21How many milliliters of 15.7 M of H2SO4 are needed to prepare 600.0 mL of 0.10 M of H2SO4?
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