Brandy S. answered 10/27/21
3 Years Teaching High School Chemistry
Hi!
The first thing you have to do is write out the equation: N2 + H2 ---> NH3
Next, you need to balance the equation so there are equal N & H on both sides: N2 + 3H2 ---> 2NH3
Now you can set up the problem. To find the number of moles of H2 when there are 2 moles of N2 you have to know stoichiometry.
We start with what the question gives us: 2 moles of N2
The next step will be to cancel our units which are moles of N2. This is where our balanced equation will come in handy. You will use the balanced equation so you have a ratio of H2 to N2. The ratio comes from the coefficients (the numbers in front).
N2 + 3H2 ---> 2NH3 The ratio in this question would be 3 mol of H2 for every 1 mol of N2
**Remember that if there is no number present, we assume it is a 1, thus 1 mol of N2
2 mol N2 x 3 mol H2 Our mol of N2 are opposite each other so they will cancel out
1 1 mol N2 leaving us with our desired units of mol H2.
Next, we just need to solve the equation like you would solve any fraction. 2 x 3 = 6 6/1 = 6
Therefore, our answer is: We need 6 mol of H2 for every 2 mol of N2
I hope this helps!