Write the equation of the Parabola

Question

Vertex at (6,8) passing through (5,10) and (5,6)

Answer 1

left ward opening parabola

x =a(y-8)^2 +6

plug in either point to solve for "a"

10 =4a +6

4=4a

a=1

x = (y-8)^2 +6 in vertex form

x = y^2-16y+72 in standard form