Question 1
a) Since the engine is the only force acting, the net force is 525 N.
Fnet=ma
525=3500a
a=525/3500
a=0.15 m/s2
b) Using v=v0+at
11.5=0+(0.15)t
t=11.5/0.15
t=76.7 seconds
Question 2
For the first mass F=m1(8)
m1=F/8
For the second mass F=m2(4)
m2=F/4
a) Therefore m2/m1 =(F/4)/(F/8) = 8/4 = 2
b) The combined mass is now m2 + m1 = F/8 + F/4 = 3F/8
Using F = (Combined Mass) x a
a= F/(3F/8)
a= 8/3 m/s2 or 2.67 m/s2
Renan C.
Because I still don't get it and no idea towards it. Help me, thank you!10/21/21

John B.
10/21/21
Renan C.
Can you explain a bit more further in question no. 2 - a and b? I'm still in a confusion. Thanks!!10/21/21