Probability x not correctly calibrated out of 3 selected, where x = 0, 1, 2, 3
We are dealing with a hypergeometric distributed variable x
Since only 2 not correctly calibrated P(x=3) = 0
P(x=0) = C(2,0)C(6,2)/C(8,2) = 15/28
P(x=1) = C(2,1)C(6,1)/C(8,2) = 12/28
P(x=2) = C(2,2),C(6,0)/C(8,2) = 1/28
mean = sum x * P(x) for x = 0 to 3:
0 * 15/28 + 1 * 12/28 + 2 * 1/28 + 3 * 0 = 14/28 = 1/2